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Answer:

A BODY is projected vertically upward with speed 40 m/s. The DISTANCE travelled by body in the last second of upward journey is [ take g=9.8 m/s  

2

 and NEGLECT effect of air resistance]

Medium

Solution

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CORRECT option is

A

4.9m

LET the horizontal distance be H and  

let the distance traveled in the last second be d

H=  

2g

u  

2

 

 

H=  

19.6

1600

 

H=81.63m

Now time taken by the body to reach a height of 81.36 m=  

g

2H

 

=4.08s

Now from equation of motion, we have

s=ut+  

2

1

gt  

2

 

H−d=(40)(t−1)−  

2

1

g(t−1)  

2

 

81.63−d=(40)(4.08−1)−  

2

1

(9.8)(4.08−1)  

2

 

d=4.85m

So, the correct answer is '4.9m'.

Explanation:



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