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Answer» Answer: A BODY is projected vertically upward with speed 40 m/s. The DISTANCE travelled by body in the last second of upward journey is [ take g=9.8 m/s 2 and NEGLECT effect of air resistance] Medium Solution verified Verified by Toppr CORRECT option is A 4.9m LET the horizontal distance be H and let the distance traveled in the last second be d H= 2g u 2
H= 19.6 1600
H=81.63m Now time taken by the body to reach a height of 81.36 m= g 2H
=4.08s Now from equation of motion, we have s=ut+ 2 1 gt 2
H−d=(40)(t−1)− 2 1 g(t−1) 2
81.63−d=(40)(4.08−1)− 2 1 (9.8)(4.08−1) 2
d=4.85m So, the correct answer is '4.9m'. Explanation: |
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