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Show graphically, the variation of the de-Broglie wavelength (lamda) with the potential (V) through which an electron is accelerated from rest. |
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Answer» Solution :Ad de-Broglie wavelength `lamda` of an electron accelerated with a POTENTIAL of V is GIVEN by: `lamda=(h)/(sqrt(2emV))`, HENCE `lamda-V` graph is shown in figure
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