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Show how a current loop acts as a magnetic dipole. Derive an expression for its magnetic moment. |
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Answer» Solution :Let us consider a circular wire carrying current which is flowing in anticlockwise direction as shown in the figure. This current loop ACTS as a magnetic dipole and lower FACE acts on S-pole and upper face acts as a N-pole. Let us find the magnetic dipole moment. Magnetic dipole moment (M) Let I be current flowing in the circular loop and A be area of the loop. It is found experimentally that the magnetic dipole moment M is (i) directly proportional to strength of current `i.e.""MpropI` (II) directly proportional to area A of the loop `i.e.""MpropA`  Combining these two parameters, we GET `MpropIA` or `M=kIA` If k = 1, then M = IA In vector FORM, `vecM=IAhatn` or `vecM=IvecA` |
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