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Show that 1 amu = 932 MeV. |
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Answer» SOLUTION :(i) The difference between the rest mass of a nucleus and the sum of the masses of its constituents is called Nuclear-mass defect. (ii) The ratio of the Binding energy of a nucleus to the number of nucleons or Binding energy per nucleons, of a nucleus is called SPECIFIC binding energy. `E=mc^(2)` Taking `m=1 amu=1.66 xx 10^(-27) ` kg and `c=2.9979 xx 10^(8) MS^(-1)` AlsoMeV `=1.6 xx 10^(-13) ` J Arriving at ` amu `=931` MeV |
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