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Show that. 2cot betha .cosec betha = cosec^2 betha |
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Answer» L.H.S=(tanα+cscβ) 2 −(cotβ−secα) 2 =tan 2 α+CSC 2 β+2tanαcscβ−cot 2 β−sec 2 α+2cotβsecα =(tan 2 α−sec 2 α)+(csc 2 β−cot 2 β)+2tanαcscβ+2cotβsecα =−1+1+2tanαcscβ+2cotβsecα =2tanαcotβ( sinβ 1 cosβ sinβ + cosα 1 sinα cosα ) =2tanαcotβ(secβ+cscα) =R.H.S HENCE proved.Step-by-step EXPLANATION: |
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