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Show that 3√2 is irrational. |
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Answer» Let us assume, to the contrary, that 3√2 is rational. That is, we can find coprime a and b (b≠0) such that 3√2=a /b Rearranging, we get √2=a/3b Since 3, a and b are integers, a/3b is rational, and so √2 is rational. But this contradicts the fact that √2 is irrational. So, we conclude that 3√2 is irrational. |
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