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Show that (4 + 3√2) is irrational. |
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Answer» Let (4+3√2) be a rational number. Then both (4+3√2) and 4 are rational. ⇒ (4+3√2 – 4) = 3√2 = rational [∵Difference of two rational numbers is rational] ⇒ 3√2 is rational. ⇒ 1/3 (3√2) is rational. [∵ Product of two rational numbers is rational] ⇒ √2 is rational. This contradicts the fact that √2 is irrational (when 2 is prime, √2 is irrational) Hence, (4 + 3√2 ) is irrational. |
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