1.

Show that 5-2i/3+i + 5+2i /3-i is real no.​

Answer»

Step-by-step EXPLANATION:

distribute the brackets using FOIL( or any method you USE)

(

5

−

2

i

)

(

5

+

2

i

)

=

25

+

10

i

−

10

i

−

4

i

2

[ this process is useful in COMPLEX numbers as the product produces a real number - the 2nd bracket is the complex conjugate of the 1st and vice-versa.]

[ NOTE :

i

2

=

(

√

−

1

)

2

=

−

1

]

⇒

(

5

−

2

i

)

(

5

+

2

i

)

=

25

+

10

i

−

10

i

+

4

=

29

a real number


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