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Show that area of circular patch of light on water as seen from a water medium is A=pi h^(2)//(n^(2)-1) where symbolshaves their usual meaning. |
Answer» Solution : `TANC=(1)/(SQRT(n^(2)-1))` `and tanC=(r)/(h)` `THEREFORE r=(h)/(sqrt(n^(2)-1))` Area `=PIR^(2)` `thereforeA=(pi h^(2))/(n^(2)-1)` |
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