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Show that cos sq 30−sin sq 30=(1−tan sq 30)÷1+tan squad 30 |
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Answer» Step-by-step explanation: = (root3/2)^2 - (1/2)^2 = 3/4 - 1/4 = 2/4 = 1/2 Now, RHS = (1 - tan^2 30) / (1 + tan^2 30) = 1 - ( 1/ root3)^2 / sec^2 30 = 1 - 1/3 / (2/ root3)^2 = (2/3)/ (4/3) =2/3 * 3/4 =1/2 Hence, LHS=RHS proved. |
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