Show that electric field intensityon the surface of a charged conductor is vecE=(sigma)/(epsi_(0))n, where sigma is the surface density of charge and vecn is the outward pointing unit normal vector.

Show that electric field intensityon the surface of a charged conducto

1.	Show that electric field intensityon the surface of a charged conductor is vecE=(sigma)/(epsi_(0))n, where sigma is the surface density of charge and vecn is the outward pointing unit normal vector.
Answer» SOLUTION :In equation (5) `EPSI= epsi_(0)` for vacuum or AIR.

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Show that electric field intensityon the surface of a charged conductor is vecE=(sigma)/(epsi_(0))n, where sigma is the surface density of charge and vecn is the outward pointing unit normal vector.

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