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Show that for the particle whose coordinate incertainty is Deltax=lambda//2pi, where lambda is its de Broglie wavelength, the velocity uncertainty is of the same order of magnitude as the particle's velocity itself. |
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Answer» <P> SOLUTION :If `Deltax=lambda//2pi=(2piħ)/(P).(1)/(2pi)=(ħ)/(P)=(ħ)/(mv)`Thus `Deltavunderset(~)gt(ħ)/(mDeltax)=v` Thus `Deltav` is of the same ORDER as `v`. |
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