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Show that in an isosceles triangle , angles opposite to equal sides are equal. |
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Answer» -step explanation:LET △ABC be an isosceles triangle such that AB =AC Then we have to prove that ∠B=∠C Draw the bisector AD of ∠A meeting BC in D Now in triangles ABD and ACD We have AB=AC (Given) ∠BAD=∠CAD (because AD is bisector of ∠AAD=AD (Common side)Therefore by SAS congruence condition we have △ABC≅△ACD⇒∠B=∠C(Corresponding PARTS of congruent triangles are equal ) |
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