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Show that p(X) =x cube -3x square +2x -6 has only one real zero |
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Answer» IT'S X^3 -3X^2 +2X-6 = 0 X^2 (X-3)+2 (X-3) = 0 (X-3) (X^2+2) = 0 X=3. BUT X=-2ROOT (THAT'S NOT POSSIBLE)SO, X=3.HOPE THIS WILL HELP YOU DEAR. PLEASE MARK MY ANSWER BRAINLIEST DEAR...♥ |
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