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Show that R.M.S. velocity of gas molecules is directly proportional to square root of its absolute temperature. |
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Answer» We know that, `P=(1)/(3)(mm)/(V)xxv^(2)` `implies" "PV=(1)/(3)xxMxxv^(2)(because" mn"=M)` But `" ""PV"="RT"" "("By Gas equation")` `:." "v^(2)=(3RT)/(M)` But `" "v_("rms")=sqrt(v^(2))` `=sqrt((3RT)/(M))` `:." "v_("ems")prop sqrt(T)` |
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