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When the elecrton in the hydrogen atom jupms from `2nd` orbit to 1st orbit, the wavelength of radiation emitted is `lambda`. When the electrons jupms from `3rd` orbit to `1st` orbit, the wavelength of emitted radiation would beA. `(27)/(32)lambda`B. `(32)/(27)lambda`C. `(2)/(3)lambda`D. `(3)/(2)lambda`

Answer» Correct Answer - `(27)/(32)lambda`


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