1.

Show that t_(99%) = 2 xx t_(90%)

Answer»

Solution :Formula : `K = (2.303)/(t) LOG""([R]_(0))/([R])`
`(t_(99%))/(t_(90%)) ==((2.303)/(t)log""(100)/(1))/((2.303)/(k) log""(100)/(10)) rArr (t_(99%))/(t_(90%)) = 2`


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