Show that the following results illustrate the law of reciprocal proportions: (i) 0.92g Mg produces 1.54g mangesium oxide. (ii) 0.41 g Mg illustrates 380mL of hydrogen at NTP from on acid. (iii) 1.25g of water results from the union of 1.11 g of oxygen with hydrogen. (Density of hydrogen at NTP=0.00009g mL^(-1))

Show that the following results illustrate the law of reciprocal propo

1.	Show that the following results illustrate the law of reciprocal proportions: (i) 0.92g Mg produces 1.54g mangesium oxide. (ii) 0.41 g Mg illustrates 380mL of hydrogen at NTP from on acid. (iii) 1.25g of water results from the union of 1.11 g of oxygen with hydrogen. (Density of hydrogen at NTP=0.00009g mL^(-1))
Answer» SOLUTION :(i) Mass of oxygen =(1.54-0.92)=0.62g 0.92g MG combines with 0.62g of oxygen 1G Mg combines with oxygen `=(0.62)/(0.92)=0.6739g` (ii) Mass of 380mL of hydrogen at NTP `=380xx0.00009g` `=0.0342g` 0.41g Mg liberates hydrogen =0.0342g 1g Mg liberates hydrogen `=(0.0342)/(0.41)=0.0834g` The RATIO of hydrogen and oxygen which combine with 1g Mg is `0.0834:0.6739`, i.e., 1:8 (iii) Mass of hydrogen `=(1.25-1.11)=0.14g` The ratio of hydrogen and oxygen in water =0.14:1.11 or 1:8 Sine, the ratio of hydrogen and oxygen is same, the LAW of reciprocal is illustrated.