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Show that the force on each plate of a parallel plate capacitor has a magnitude equal to (1/2)QE, where Q is the charge on the capacitor, and E is the magnitude of electric field between the plates. Explain the origin of the factor 1/2. |
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Answer» Solution :Force `=1/2"QEWork DONE"=1/2V XX Q` `F xx d =1/2 xx E.d xx Q""F=1/2 QE` The physical ORIGIN of the factor `1/2` in the force formula lies in the fact that just outside the conductor, field is E and insde it is zero. So, the average VALUE `E/2` CONTRIBUTES to the force. |
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