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Show that the function y = A cos 2x – B sin 2x is a solution of the differential equation \(\frac{d^2y}{dx^2}+4y=0.\) |
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Answer» The differential equation is \(\frac{d^2y}{dx^2}+4y=0\) and the function that is to be proven as solution is y = A cos 2x – B sin 2x, now we find the value of \(\frac{d^2y}{dx^2}.\) \(\frac{dy}{dx}\) = = –2A sin 2x – 2B cos 2x \(\frac{d^2y}{dx^2}\) = –4A cos 2x + 4B sin 2x Putting the values in the equation, we get, –4A cos 2x + 4B sin 2x + 4(A cos 2x – B sin 2x) = 0, 0 = 0 As, L.H.S = R.H.S. the equation is satisfied, so hence this function is the solution of the differential equation. |
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