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Show that the magnetic field B at a point in between the plates of a parallel plate capacitor during charging is B=(mu_(0)in_(0)r)/(2).(dE)/(dt) (symbols having usual meaning). |
Answer» Solution :Consider current `I_(d)` between plates of parallel plate capacitor. Magnetic field at perpendicular DISTANCE R from one plate of capacitor, `B=(mu_(0)I)/(2pi r)=(mu_(0))/(2pi r)I_(d)=(mu_(0))/(2pi r)xx(in_(0)(d phi_(E ))/(DT)) "" [because I_(d)=in_(0)(d phi_(E ))/(dt)]` `=(mu_(0)in_(0))/(2pi r)[(d)/(dt)(E pi r^(2))]` `=(mu_(0)in_(0))/(2pi r).pi r^(2)(dE)/(dt)` `B=(mu_(0)in_(0)r)/(2).(dE)/(dt)[because phi_(E )=EA=E xx pi r^(2)]` |
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