Show that the magnetic moment of an atom is M = 1/2 eomegar^2 , where e the charge of an electron , omega - angular speed of electron and r - the radius of electron orbit.

Show that the magnetic moment of an atom is M = 1/2 eomegar^2 , where

1.	Show that the magnetic moment of an atom is M = 1/2 eomegar^2 , where e the charge of an electron , omega - angular speed of electron and r - the radius of electron orbit.
Answer» Solution :The electrons are revolving round of nucleus of an atom. If .e. is the charge of an electron and T its period of revolution , then Current `I=e/T=(eomega)/(2PI)`. Since `T=(2pi)/OMEGA, omega` is the angular VELOCITY . If `A = pir^2` , is the area of the orbit of radius .R. , then MAGNETIC moment of the atom, `M=IA=(eomega)/(2pi).pir^2=1/2eomegar^2`

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Show that the magnetic moment of an atom is M = 1/2 eomegar^2 , where e the charge of an electron , omega - angular speed of electron and r - the radius of electron orbit.

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