1.

Show that the matrix B′ AB is symmetric or skew-symmetric according as A is symmetric or skew-symmetric.

Answer»

We suppose that A is a symmetric matrix, then A′ = A 

Consider (B′ AB)′ ={B′ (AB)}′ = (AB)′ (B′ )′ [ (AB)′ = B ′ A′ ] 

= B′ A′ (B) [ (B′ )′ = B] 

= B′ (A′ B) = B′ (AB) [ A′ = A] 

⇒ (B′ AB)′ = B′ AB 

which shows that B′ AB is a symmetric matrix. 

Now, we suppose that A is a skew-symmetric matrix. 

Then, A′ = − A 

Consider (B′ AB)′ = [B′ (AB)]′ = (AB)′ (B′ )′ [(AB)′ = B′ A′ and (A′ )′ = A]

= (B′ A′ )B = B′ (−A)B= − B′ AB [ A′ = − A] 

⇒ (B′ AB)′ = − B′ AB 

which shows that B′ AB is a skew-symmetric matrix.



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