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| 1. | Show that the motion of the pendulum is SHM for small angular displacement | 
| Answer» Begin witha diagram of the system, anddefinition of directions. Vertically upand clockwise rotations arepositive. It must be recalled that in SHM force is proportional to displacement from equqilibrium.The key assumptions to make are: the string is taught throughout the motion of the pendulum, the string doesn't break thtroughout the motion of the pendulum, the initial angle of displacement from vertical is small, there is no drag. Take theangular displacement from veritcal to bex, and look at the forces on the particle. Assumptions 1) and 2)implythat there is no motion parrallel to the string, and hence the tension in the string must be equal magnitude to the weight of the mass parallel to the string. Hence the resultant force must act perpendicular to the direction of the string. Using trigonometry, this force (F)is: -mgsin(x). where g is the acceleration due to gravity. Now, in the small angle limit sin(x) ~ xso F=-mgsin(x) becomes F~-mgx. Since x is displacement from equilibrium, the system undergoesSHM. 
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