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Show that the orbital magnetic dipole moment of a revolving electron is` evr//2. ` |
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Answer» Let, r, v and T be the orbital radius, speed and period of motion of the electron. Then, `" "T=(2pir)/(v)` The orbital motion of the electron constitutes a loop of conventional current I in the opposite sense of its revolution. `I=(e)/(T)=(ev)/(2pir)` So the magnetic dipole moment associated with this electronic current loop is given by `M_(o)=IxxA=("ev")/(2pir)xxpir^(2)=(1)/(2)xxevr` `implies" "=("evr")/(2)` |
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