1.

Show that the points (a, b + c), (b, c + a), (c, a + b) are collinear.

Answer»

For three points to be collinear, the area of the triangle formed by the three points should be zero. 

∴ Area of D formed by the given three points

\(\frac{1}{2}\) [a((c + a) – (a + b)) + b((a + b) – (b + c)) + c((b + c) – (c + a))]

\(\frac{1}{2}\) [a(c – b) + b(a – c) + c(b – a)] = \(\frac{1}{2}\) [ac – ab + ba – bc + cb – ca] = 0.

Hence (a, b + c), (b, c + a) and (c, a + b) are collinear.



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