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Show that the relation R = {(a, b): a > b} on N is transitive but neither reflexive nor symmetric. |
Answer» It is given that R = {(a, b): a > b} Reflexive- If a ∈ R we get (a > b) So (a, b) ∉ R for a ∉ R Hence, R is not reflexive. Symmetric- We know that (3, 4) ∈ R but (4, 3) ∉ R Hence, R is not symmetric. Transitive- Consider (a, b) ∈ R and (b, c) ∈ R It can be written as a > b and b > c So we get a > c where (a, c) ∈ R Hence, R is transitive. Therefore, R is transitive but neither reflexive nor symmetric. |
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