InterviewSolution
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Show that the set G = {a + b√2/a, b ∈ Q} is an infinite abelian group with respect to Binary operation addition. Satisfies closure, associative, identity and inverse properties. |
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Answer» (i) Closure axiom : Let x, y ∈ G. Then x = a + b√2, y = c + d√2; a, b, c, d ∈ Q. x + y = (a + b√2) + (c + d√2) = (a + c) + (b + d) √2 ∈ G, Since (a + c) and (b + d) are rational numbers. ∴ G is closed with respect to addition. (ii) Associative axiom : Since the elements of G are all real numbers, addition is associative. (iii) Identity axiom : There exists 0 = 0 + 0√2 ∈ G such that for all x = a + b√2 ∈ G. x + 0 = (a + b√2) + (0 + 0√2) = a + b√2 = x Similarly, we have 0 + x = x. ∴ 0 is the identity element of G and satisfies the identity axiom. (iv) Inverse axiom: For each x = a + b√2 ∈ G, there exists -x = (-a) + (-b) √2 ∈ G such that x + (-x) = (a + b√2) + ((-a) + (- b) √2) = (a + (-a)) + (b + (-b)) √2 = 0 Similarly, we have (- x) + x = 0 . ∴ (- a) + (-b) √2 is the inverse of a + b√2 and satisfies the inverse axiom. (v) Commutative axiom: x + y = (a + c) + (b + d) √2 = (c + a) + (d + b) √2 = (c + d√2) + (a + b√2) = y + x, for all x, y ∈ G. ∴ The commutative property is true. ∴ (G, +) is an abelian group. Since G is infinite, we see that (G, +) is an infinite abelian group. |
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