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Show that the square of an odd positive integer is of the form 8m + 1, for some whole number m. |
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Answer» Any positive odd integer is of the form 2q + 1, where q is a whole number. Therefore, (2q + 1)2 = 4q2 + 4q + 1 = 4q (q + 1) + 1, ...... (1) q (q + 1) is either 0 or even. So, it is 2m, where m is a whole number. Therefore, (2q + 1)2 = 4.2 m + 1 = 8 m + 1. [From (1)] |
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