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Show that the statement . p : 'If x is a real number such thatx^(3)+ 4x=0, then x=0' is true by Method of contradiction

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Answer :METHOD of CONTRADICTION :
LET x ≠0, and let x=p,p`in` R and p is a root of`x^(3)+4x=0=>p^(3)+4p=0=>p(p^(2)+4)=0.` but p ≠ 0 (assumption),also`p^(2)+4 ≠ 0=> p(p^(2)+4),i.e., p^(3)+4p ≠ 0` This contradicts the given statement. So our assurnption that x≠0is wrong Hence, x =0.


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