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Show that the term containing to does not exist in the expansion of `(3x-1/(2x))^8` |
Answer» `T_(r+1) = (-1)^(r)*^(8)C_(r)*(3x)^((8-r)) .(1/(2x))^(r)` `rArr T_(r+1) = (-1)^(r)*^(8) C_(r)*3^(8-r)*1/2^(r) *x ^((8-2r)).` Now, `8-2r = 3 rArr r=5/2`, which is a fraction. |
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