Show that the the sequence defined by ` T_(n) = 3n^(2) +2 ` is not an

1.	Show that the the sequence defined by ` T_(n) = 3n^(2) +2 ` is not an AP.
Answer» We have, `t_n=3n^(2)+2` On replacing n by `(n-1),` we get `t_(n-1)=3(n-1)^(2)+2` `implies t_(n-1)=3n^(2)-6n+5` `therefore t_n-t_(n-1)=(3n^(2)+2)-(3n^(2)-6n+5)` `" "=6n-3` Clearly, `t_n-t_(n-1)` is not independent of n and therefore it is not constant. So, the given sequence is not an AP.

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Show that the the sequence defined by ` T_(n) = 3n^(2) +2 ` is not an AP.

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