1.

Show that y = ae2x + be–x is a solution of the differential equation \(\frac{d^2y}{dx^2}-\frac{dy}{dx}-2y=0.\)

Answer»

The differential equation is \(\frac{d^2y}{dx^2}-\frac{dy}{dx}-2y=0\) and the function that is to be proven as solution is y = ae2x + be–x, now we need to find the value of \(\frac{dy}{dx}\) and \(\frac{d^2y}{dx^2}.\)

\(\frac{dy}{dx}\) = 2ae2x – be–x

\(\frac{d^2y}{dx^2}\) = = 4ae2x + be–x

Putting these values in the equation, we get,

4ae2x + be–x –(2ae2x – be–x) – 2(ae2x + be–x) = 0,

0 = 0

As, L.H.S = R.H.S. the equation is satisfied, so hence this function is the solution of the differential equation.



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