1.

SI unit of magnetic field is called tesla, where 1 T = 1 N/A-m

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SOLUTION :As per relation `F = Q V B sin theta, B = (F)/(qv sin theta) implies 1 "tesla" = (1 N)/((1C) xx (1 ms^(-1))) = (1N)/(1 A m) = 1 N//A-m`


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