1.

SI unit of permeability is

Answer»

`(Am)/T`
`(Tm)/A`
`T/(Am)`
`A/(Tm)`

Solution :`dB=mu_(0)/(4PI)*(Idlsintheta)/r^(2)`
`thereforemu_(0)=(4pidBr^(2))/(Idlsintheta)`
Since, `4piandsintheta` are UNITLESS,
`THEREFORE` Unit of `mu_(0)=(Tm^(2))/(Am)=(Tm)/A`


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