1.

SI unit of the ratio of Electric flux and Magnetic flux is

Answer»

`m`
`MS^(-1)`
`ms^(-2)`
`ms`

Solution :`("ELECTRIC flux")/("Magnetic flux")= (phi_(E) )/( Phi_(m) ) = (AE)/(AB) =(E )/( B)=(NC^(-1) )/(NA^(-1) m^(-1) ) = (mA)/( C)`
but `C= AS`
`therefore (phi_(E))/( phi_(m) ) = (mA)/( AS) = (m)/(S)`
`therefore` Unit of `(phi_E)/( phi_m)` is the unit of velocity of light `=ms^(-1)`.


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