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सिद्ध कीजिये कि यदि `theta + phi`= अचर , तब `sin theta sin phi` का मान उच्चिष्ठ होगा यदि `theta = phi` |
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Answer» ` y = sin theta sin phi = 1/2 [2 sin theta sin phi]` ` = 1/2 [cos(theta- phi) - cos (theta+ phi)]` `rArr (dy)/(d theta) = 1/2 [-sin (theta - phi)] - 0` व ` (d^(2)y)/(d theta^(2)) = - 1/2 cos (theta - phi)` उच्चिष्ठ तथा निम्निष्ठ मान के लिए ` (dy)/(d theta) = 0` ` rArr 1/2 - sin (theta - phi) = 0 rArr theta = phi` ` rArr theta = phi "पर" , (d^(2)y)/(d theta^(2))=`ऋणात्मक |
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