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side lengths bc = a , ca = b , ab = c of a triangle abc satisfy a³+b³+c³/a+b+c =c² find angle bca in degree please give correct answer its very urgent |
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Answer» Correct option is 45 In △ABC, SIDES a,b,c ⇒ c 2 =2ab [ given ] ----- ( 1 ) ⇒ a+c 2 =3b 2 [ Given ] ----- ( 2 ) ⇒ a 2 +2ab=3b 2 [ From ( 1 ) ] ⇒ a 2 +2ab+b 2 =4b 2 [ Adding b 2 on both sides ] ⇒ (a+b) 2 =4b 2
⇒ a+b=±2b Since, a,b,c are sides then they are always positive. ∴ a+b=2b ∴ a=b Substitute a=b in EQUATION ( 1 ) we get, ⇒ c 2 =2a 2
⇒ c= 2 a We can see, c 2 =a 2 +b 2
c 2 =a 2 +a 2
c= 2 a ∴ We can see ABC is RIGHT angled triangle and c is the hypotenuse. ⇒ ∠C=90 o
⇒ ∠A+∠B=90 o
⇒ ∠A+∠A=90 o [ Base angles of an equal sides also an equal ] ⇒ 2∠A=90 o
∴ ∠A=45 o
∴ ∠BAC=45 o |
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