Sides of triangle are 70 cm ,80cm,90cm find the area and length of the

1.	Sides of triangle are 70 cm ,80cm,90cm find the area and length of the shortest altitude (use root 5=2.23
Answer» Answer: A= 70 cm B= 80 cm C= 90 cm Semi-perimetre = (70+80+90)/2 = 240/2 = 120 cm Area of ∆ = √{120(120-70)(120-80)(120-90)} = √{120×50×40×30} = √{4×3×10×5×10×3×10×4×10} = 4×3×100√5 = 1200× 2.23 = 1200× 223/100 = 2676cm^2 THEREFORE, Area of ∆ is 2676cm^2

Sides of triangle are 70 cm ,80cm,90cm find the area and length of the shortest altitude (use root 5=2.23

Answer»

Answer:

A= 70 cm

B= 80 cm

C= 90 cm

Semi-perimetre = (70+80+90)/2

= 240/2

= 120 cm

Area of ∆ = √{120(120-70)(120-80)(120-90)}

= √{120×50×40×30}

= √{4×3×10×5×10×3×10×4×10}

= 4×3×100√5

= 1200× 2.23

= 1200× 223/100

= 2676cm^2

THEREFORE, Area of ∆ is 2676cm^2

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Sides of triangle are 70 cm ,80cm,90cm find the area and length of the shortest altitude (use root 5=2.23

Answer:

A= 70 cm

B= 80 cm

C= 90 cm

Semi-perimetre = (70+80+90)/2

= 240/2

= 120 cm

Area of ∆ = √{120(120-70)(120-80)(120-90)}

= √{120×50×40×30}

= √{4×3×10×5×10×3×10×4×10}

= 4×3×100√5

= 1200× 2.23

= 1200× 223/100

= 2676cm^2

THEREFORE, Area of ∆ is 2676cm^2

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