Silver chloride is prepared by (i) dissolving 0.5 g of silver wire in nitric acid and adding excess of hydrochloric acid to silver nitrate formed. The silver chloride precipitated is separated, washed and dried. The weight of silver chloride is 0.66 g. (ii) heating 1 g of silver metal in a current of dry chlorine gas till the metal is completely converted into its chloride. It is found to weight 1.32 g. Illustrate the law of constant composition by the above data.

Silver chloride is prepared by (i) dissolving 0.5 g of silver wire in

1.	Silver chloride is prepared by (i) dissolving 0.5 g of silver wire in nitric acid and adding excess of hydrochloric acid to silver nitrate formed. The silver chloride precipitated is separated, washed and dried. The weight of silver chloride is 0.66 g. (ii) heating 1 g of silver metal in a current of dry chlorine gas till the metal is completely converted into its chloride. It is found to weight 1.32 g. Illustrate the law of constant composition by the above data.
Answer» SOLUTION :`%" of AG in AgCl in 1st case"=(0.5)/(0.66)xx100=75.76%` `%" of Cl"=24.24%` `%" of Ag in AgCl in 2ND case"=(1)/(1.32)xx100=75.76%` `5" of Cl"=24.24%`