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Silver crystallises in face-centered cubic unit cell. Each side of this unit cell has a length of 400 pm. Calculate the radius of the silver atom. (Assume the atoms just touch each other on the diagonal across the face of the unit cell. That is each face atom is touching the four corner atoms) |
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Answer» Solution :For fcc unit CELL the relation between EDGE length and RADIUS is GIVEN by `r=(a)/(2SQRT2)` Given a = 400 pm `therefore""r=(400)/(2sqrt2) or r =" 141.4 pm."` |
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