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Silver crystallises in fcc lattice. If edge length of the cell is 4.07 xx 10^(-8) cm and density is 10.5 g cm^(-3), calculate the atomic mass of silver. |
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Answer» Solution :The relation between atomc MASS, density, edge length and z is given by `M=(d xx a^(3)xxN_(A))/(z)` Substituting the VALUES, we get `M=((10.5 g CM^(-3))xx(4.077xx10^(-8)cm)^(3)xx6.022xx10^(23)mol^(-1))/(4)="107.09 g mol"^(-1)`. |
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