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Silver crystallizes in a face centered cubic structure. If the edge length is 4.077 xx 10^(-8) cm and density is 10.5 g//cm^(3), calculate the atomic mass of silver. |
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Answer» Solution :`d = (ZM)/(a^(3)N_(A))` `M = (d XX a^(3) xx N_(A))/(Z)` `= (10.5 xx (4.077)^(3) xx 10^(-24) xx 6.022 xx 10^(23))/(4)` `= (428.50)/(4)` The atomic mass of silver (M) = 107.12 u |
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