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Silver forms ccp lattice and x-ray studies of its crystals show that the edge length of its unit cell is 408.6 pm. Calculate the density of silver. (Atomic mass of Ag = 107.9 u) |
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Answer» Solution :Since it is, cop the number of atoms PER UNIT cell, Z = 4 Molar MASS of silver,`M=108 g mol^(-1)` Edge length of the unit cell, `a=408.6` pm. `=408.6xx10^(-10)cm`. DENSITY of the unit cell `d=(ZM)/(N_(A)a^(3))=(4xx108 gmol^(-1))/(6.022xx10^(23)mol^(-1)xx(408.6xx10^(-10)cm)^(3))` `d=10.51 gmol^(-3)`. |
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