1.

Silver forms ccp lattice and X-ray studies of its crystals show that the edge length of its unit cell is 408.6 pm. Calculate the density of silver (Atomic mass = 107.9u).

Answer»


Solution : Edge length = 408.6 pm = `4.086 xx 10^(-8)` CM
M=107.9 U, For ccp, Z = 4, `d =(ZM)/(N_A a^3)G cm^(-3)=(4 xx 107.9)/(6.023 xx 10^(23) xx (4.086)^3 xx 10^(-24)cm^3)= 10.5 g cm^(-3)`


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