1.

Silver is electro-deposited on a metallic vessel of surface area 800 cm^(2) by passing current 0.2 ampere for 3 hours. Calculate the thickness of silver deposited. Given the density of silver as 10.47 g/cc (Atomic mass of Ag=107.92amu)

Answer»

Solution :Quantity of electricity passed`=0.2xx3xx60xx60C=2160C`
`At^(+)+e^(-)toAg`
96500 C deposit `Ag=107.92g`
2160 C will deposit `Ag=(107.92)/(96500)xx2160g=2.4156g`
VOLUME DEPOSITED`=(Mass)/(Density)=(2.4156)/(10.47)c c=0.2307c c`
THICKNESS deposited`=("Volume")/("Area")=(0.2307)/(800)=2.88xx10^(-4)cm`


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