Silver is uniformly electro-deposited on a metallic vessel of surface area of 900 cm^2 by passing a current of 0.5 ampere for 2 hours. Calculate the thickness of silver deposited.

Silver is uniformly electro-deposited on a metallic vessel of surface

1.	Silver is uniformly electro-deposited on a metallic vessel of surface area of 900 cm^2 by passing a current of 0.5 ampere for 2 hours. Calculate the thickness of silver deposited.
Answer» Solution :CALCULATIONS of MASS of Ag deposited: The electrode reaction is `Ag^(+)+e^(-) to Ag` The QUANTITY of ELECTRICITY passed `= Current times time` `=0.5 (amp.) times 2 times 60 times 60 (sec)` =3600 C. From the electrode reaction, it is clear that 96500C of electricity deposit Ag=108g 360 C of electricity will deposit Ag=`108/96500 times 3600` =4.03g Calculation of thickness: Let the thickness of deposited be x cm. Mass= Volume `times` density = Area `times` thickness `times` density (Volume= Area` times` thickness) `4.03g=900(cm^2) times x (cm) times 10.5 (G cm^-3)` `x=4.03/(900 times 10.5)=4.26 times 10^-4 cm`