1.

Silver metal crystallises with a face centred cubic lattice. The length of unit cell is formed to be 4.077 xx 10^(-8) cm. Calculate atomic radius and density of silver. (Atomic mass of Ag = 108 u, N_(A) = 6.023 xx 10^(23) mol^(-1)).

Answer»

Solution :GIVEN : `a = 4.077 xx 10^(-8)` cm, Z = 4, M = 108 g `MOL^(-1)`
`N_(A) = 6.023 xx 10^(23)`
`d = (Z xx M)/(a^(3) xx N_(A))`
`= (4 xx 108)/((4.077 xx 10^(-8))^(3) xx 6.023 xx 10^(23))`
`= 6.22 g//cm^(3)`
For fcc `r = (a)/(2 SQRT(2))`
`= (4.077 xx 10^(-8) cm)/(2 sqrt(2))`
`= 1.44 xx 10^(-8)` cm


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