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Answer» nGiven:-2√6/(√2+√3) + 6√2/(√6+√3) - 8√3/(√6+√2)FIND:-Value of GIVEN terms Explanation☞2√6/(√2+√3) + 6√2/(√6+√3) - 8√3/(√6+√2)Rationalize denominators of all term ➠ 2√6(√2-√3)/(√2-√3)(√2+√3) + 6√2(√6-√3)/(√6-√3)(√6+√3) - 8√3.(√6-√2)/(√6-√2)(√6+√2)☛ Using REQUIRED Formula★ (x-y)(x+y) = x² - y²So,➠ 2√6.(√2-√3)/[(√2)²-(√3)³] + 6√2(√6-√3)/[(√6)²-(√3)²] - 8√3.(√6-√2)/[(√6)²-(√2)²]➠ 2√6(√2-√3)/(2-3) + 6√2(√6-√3)/(6-3) - 8√3.(√6-√2)/(6-2)➠ 2√6.(√3-√2) + 2√2.(√6-√3) - 2√3.(√6-√2)➠ 2.√18 - 2√12 + 2.√12 - 2.√6 - 2.√18 + 2.√6➠ ( 2.√18 - 2.√18) + (2.√12 - 2.√12) + (2.√16 - 2.√16)➠ 0 + 0 + 0➠ 0 [ Ans.]________________ |
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