1.

Simplify x b-c/bc × x c-a /ca × xa-b/ab​

Answer»

-step EXPLANATION:Given: (xa/xb)^1/ab( xb /xc)^1/bc(xc/xa)1/caWe NEED to prove the GIVES equation is unity that si 1LHS=(xa/xb)^1/ab( xb /xc)^1/bc(xc/xa)1/caUsing laws of exponents= (xa/xb)1/ab( xb /xc)1/bc(xc/xa)1/CA= x(a-b)/ab * x^(b-C)/bc * x^(c-a)/ca= x[(a-b)/ab + (b-c)/bc + (c-a)/ca]= x[c(a-b)/abc + a(b-c)/abc + b(c-a)/abc ]= x { [c(a-b)+ a(b-c) + b(c-a) ]/abc }= x ( ac – bc + ab – ac + bc – ab ] /abc= x 0/abc= x0= 1



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